28=6y+2+2y^2-6

Solution for 28=6y+2+2y^2-6 equation:

28=6y+2+2y^2-6

We move all terms to the left:

28-(6y+2+2y^2-6)=0

We get rid of parentheses

-2y^2-6y-2+6+28=0

We add all the numbers together, and all the variables

-2y^2-6y+32=0

a = -2; b = -6; c = +32;
Δ = b2-4ac
Δ = -62-4·(-2)·32
Δ = 292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{292}=\sqrt{4*73}=\sqrt{4}*\sqrt{73}=2\sqrt{73}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{73}}{2*-2}=\frac{6-2\sqrt{73}}{-4}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{73}}{2*-2}=\frac{6+2\sqrt{73}}{-4}
$